If it's not what You are looking for type in the equation solver your own equation and let us solve it.
24x=12x^2
We move all terms to the left:
24x-(12x^2)=0
determiningTheFunctionDomain -12x^2+24x=0
a = -12; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-12)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-12}=\frac{-48}{-24} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-12}=\frac{0}{-24} =0 $
| 5y-8=3y÷ | | 8x-24=3x+46 | | 8y-14=y+35 | | 2(1/6)-w/7=1 | | 21/6-w/7=1 | | -20x+44=5x-106 | | 7w+8-w-3=3w+11 | | 1/6x-3/2=2/1x-6/5 | | -x-3=5x-33 | | 3x+5(4x)=8x-14 | | -3/4=w+1 | | 2(x10)=4 | | 23x-7=57 | | 4^x+20=77 | | -4m-11=-19 | | x+26+2x=180 | | 3(2c+7)=4c+39 | | T=4s+4.28 | | j/2-15=-12 | | -0.67x-0.4=0.5 | | 2(2c+7)=4c+39 | | 1+2/3x=-20 | | 4(2x+5)=3x+x | | -31=8x+1 | | 5(r-3)-17+r=2(r+8)-12 | | 6z+8=9z+7 | | 3(x-9)=10x-9-7x | | 6+7z-5=-4z+16+8z | | s/2-7=9 | | 15−4f=43 | | 15−-4f=43 | | 6x-66=66-6x |